杭电ACM 1001 Sum Problem - neuxxm's Blog - 本为贵公子,平生实爱才。感时思报国,拔剑起蒿莱。
杭电ACM 1001 Sum Problem
Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 108140 Accepted Submission(s): 24596
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1 100
Sample Output
1 5050
#include <stdio.h> int main(){ int n, sum; while (scanf("%d", &n) == 1){ sum = 0; while (n != 0){ sum += n--; } printf("%d\n\n", sum); } return 0; }